In the following, simple methods of calculation are given for the most important structures. The annexes contain numerical examples which make mathematical procedures simple to understand.
The mathematical procedures for the individual components of an intake structure are in many cases the same. Thus the course of calculation and the formulas to be applied are the same for the retaining weir in the river and the free overfall weir in the lateral intake, e.g. between forebay and diversion canal (Fig. 26).
The most important calculations necessary for the design of the
intake structure relate to
- free overfall weir as a retaining or diversion weir,
- discharge below a dam wall in the canal,
- free overfall side weir as spillway or as structure for intake on the river bank,
- bottom intake in a special case,
- lateral intake with repelling groin.
Irrespective of whether intake structures are selected with or
without damming of the river, the structures should be so designed
that
- at times of the lowest discharge, the required amount of water QA can always be diverted,
- all floods, including the design flood, can be evacuated without damage being caused to structures or objects, or danger to life and limb,
- the amount of water flowing into the canal is limited to the amount of water to be diverted QA This can be achieved by installing suitable structures in the inlet or by spillways.
Fig. 32: Limitation resp. evacuation
of diverted water through a weir or a
sluice
For calculation purposes, the intake structure or weir is assumed to be as schematically represented in Fig. 33. If the weir is constructed at right angles to the river or the intake so that the water's approach is vertical, the discharge over the weir can be determined by means of the following formula:
Fig. 33: Dimensioning of fixed weirs
Weir formula (or Poleny formula)
(in m³/s)
The symbols are as follows (cf. Fig. 33):
Q = discharge over the downstream face in m³/s, c = correction factor for submerged overfall, m = weir coefficient, b = weir crest width in m, g = acceleration due to gravity = 9.81 m/s², hü = weir head in m.
- Weir coefficient m
This coefficient depends upon the crest form of the weir. In Fig. 33 the coefficients are given for the most typical crest forms. For the construction of weir bodies with vertical headwater side in rivers transporting a large amount of bed load, it should be remembered that after a prolonged period of operation, this weir will have the same effect as a broad, round-crested weir due to the alluvial deposits in front of the weir face. In this case, the discharge capacity would be smaller due to the smaller weir coefficient.
- Correction factor c
The correction factor c allows for the influence of the tail water level upon the discharge over the weir:
- for the free overfall c = 1,
- for the submerged overfall, c is to be taken from the graphical representation in Fig. 33.
Whether an overfall is free or submerged depends upon the height of the tail water level in relation to the position of the weir crest (Fig. 34).
- If h' < 0, the overfall is free.
- If h' > 0 and if there is a limiting depth tlimit above the weir crest, the overfall is submerged.
- If h' > 0 but the discharge flows over the weir crest, the overfall is submerged.
For the design of a weir, in most cases the height of the weir crest at a given weir length (e.g. width of the river/canal) must be found. For this purpose, the following quantities and dimensions in accordance with the weir type (retaining weir or diversion weir) must be specified or known:
Retaining weir
- maximum discharge (flood event) over the weir
- maximum permissible headwater level h0
- weir type with weir coefficient tail water level hu when the maximum discharge is evacuated
Fig. 34: Discharge over a weir
Diversion weir
- minimum amount of water to be diverted
- minimum headwater level h0
- weir type with weir coefficient
- tail water level hü when the minimum amount of water to be diverted is evacuated
If these data are available, the weir head hü of the retaining weir in the case of flood (maximum load) can be determined. The weir body height is then
w = h0 - hü
This allows the elevations of the water surface in the river upstream of the weir to be determined by the weir formula for any discharge. The weir crest of the intake structure must be high enough so that at the lowest discharge, the required amount of water for power generation is evacuated over the diversion weir by a sufficient weir head (cf. Fig. 35).
Numerical examples of the calculation of a free and submerged overfall weir as well as an overfall over a weir with stilling basin or race floor are given in Annexes 3 to 5.
Fig. 35: Relationship between
diversion weir and retaining weir
Fig. 36: Principle of the side weir
with the hydraulic characteristics. Q0 headwater discharge,
Qu tail water discharge, QA evacuated amount of water, w
weir height, L weir length, h0 weir head in the headwater,
hu weir head in the tail water, hm mean weir head,
hEu energy head in the tail water, v0,u flow velocity in
the headwater, tail
water
A side weir (cf. Fig. 36) is always involved when a weir is approached obliquely or is situated parallel to the channel line to evacuate the amounts of water QA. This oblique approach occurs when the weir is constructed parallel to the river bank or power canal, for example. The calculation of the discharge capacity of a side weir is made with the following weir formula:
(in m³/s)
where L = length of side weir in m, hm = mean weir head in m, mx = reduced weir coefficient = 0.95 · m (for m cf. Fig. 33), c = correction factor (cf. also section 3.2).
An important prerequisite for the application of this formula is that the discharge in the headwater be a flowing one. This condition is fulfilled when Froude's number is smaller than 0.75:
where v0 = velocity in the headwater in m/s,
(in m/s, for the symbols cf.
Fig. 36),
g = acceleration due to gravity = 9.81
m/s²,
h0 = estimated weir head at the beginning of the side
weir in m (cf. calculation example in Annex 6), w = weir crest height in
m.
In the place of the weir head h, a mean weir head hm in m is
used. It is the mean value of the smaller weir head ho at the beginning of the
side weir which increases along the downstream face up to the maximum weir head
hu at the end of the side weir. The weir head hu is
determined by the discharge characteristic of the river or canal, i.e. it
corresponds approximately to the difference between the given tail water level
tu and the weir crest height w.
hu = tu - w (in m)
The weir head ho must first be estimated. For this purpose, the known or determined quantities such as weir crest height w, tail water level tu, inflow to the headwater Q0, and headwater width B0 are introduced into the formula
with the energy head
(in m/s, cf. Fig. 36)
(in m/s)
a = 1.1 velocity coefficient
and solved iteratively. After the weir head ho has been determined, the mean weir head
(in m)
is calculated and the value n read off from the diagram in Fig. 37 as a function of hm and Qu > 0 (residual amount of water in the tail water) and/or Qu = 0 (case: confined tail water; this is the case when the main flow is confined by a sluice and all the water is led over the side weir: QA = Q0). This value n is multiplied by a and yields the new value
a = n a (a= 1.1)
In the above-mentioned formula, this new value a replaces the former value a = 1.1 (n results from Fig. 37).
Repeating the iterative solution of this equation using a we obtain an improved estimated value of
h0.
With the mean weir head then determined, the weir length is
(in m)
The procedure is shown systematically in the following. A numerical example is given in Annex 6.
Fig. 37: Correction factor n for side
weir
calculation
The calculation of the outflow below a dam wall or a sluice is one of the most common tasks of hydraulic engineering. As compared with the relatively small openings for bottom outlets of dams, the width of the outflow opening for the outflow below the sluice can be considered large compared with its height. In these cases, the discharge can be ,dealt with as a two-dimensional flow problem and calculated with the following formula:
(in m³/s)
where k = correction factor for submerged discharge; for free discharge k = 1 (cf. Fig. 38), m = discharge coefficient; this coefficient chiefly takes the jet contraction into account, a = height of the outflow opening in m, B = width of the outflow opening in m, h = impounding head in front of the sluice or the dam wall in m, g= acceleration due to gravity = 9.81 m/s².
The discharge coefficient for the vertical sluices which are most frequently used depends upon h/a
m = 0.55 - 0.60 (limiting value)
For rough dimensioning, a value m = 0.6 can be assumed.
The correction factors k for the submerged discharge are given
in Fig. 38. For free discharge, i.e. when the tail water is not an influencing
factor k = 1.
The tail water is an influencing factor when the shooting jet
is impounded at the sluice opening directly behind the sluice (cf. Fig. 38).
This discharge behaviour is dependent upon the tail water level (and, thus, upon
the dimensioning quantities of the power canal, the headwater level and the
sluice opening).
For the dimensioning of the outflow below a sluice, mainly the following quantities are specified or must be fixed:
- height of the sluice opening a (is fixed),
- headwater level (minimum, maximum), known from the canal calculation,
- tail water level hu (dependent upon the amount of water to be evacuated and upon the dimensioning of the tail water canal),
- sluice width B, dependent upon the canal width.
With the formula given above, QA can now be
determined. It must first be ascertained whether or not the discharge is
free.
For this purpose the ratio h/a is formed.
From Fig. 38d), with, for
example, s = 0.7 for h/a, the limiting value
hu/a limit. is determined.
The discharge is free when
QA is then determined for the conditions assumed. In
most cases, however, the necessary amount of outflow QA is known, and
therefore only the height of the sluice opening a must be determined.
After
these quantities have been fixed, the sluice openings a necessary for the
evacuation of the corresponding amounts of water can be determined.
For this
purpose, the above-mentioned formula must be transformed with respect toe:
The following procedure is followed:
- If there is a free discharge (i.e. k = 1), the formula given above is used to determine a.
- h/a is formed and the limiting value for hu/a is ascertained in accordance with Fig. 38d).
- Exist. hu/a is compared with hu/a limit. If hu/a < hu/a limit., the assumption is correct. The calculation is complete. If the assumption is not correct, the calculation is continued.
- For hu/a > hu/a limit., the k value for exist. hu/a is determined with the curve for h/a from Fig. 38e).
- With this k value QAexist. is calculated; it proves to be smaller than QA determined
- In order to evacuate QAdeterm. a must be increased. In first approximation, anew = a/k.
- Now h/a and hu/a are again checked in accordance with Figs. 38d) and e).
- The k values and the values anew and aold are compared.
- The calculation is repeated by a new adaptation, if necessary, until the deviation is small and QA can be evacuated.
Numerical examples are given for both cases in Annex 7.
Fig. 38: Dimensioning of the
discharge below a sluice, d contraction
coefficient
a) Discharge below a sluice
b. Free discharge
c) submerged discharge
d) Limit between free and submerged value
e) k value for the submerged discharge as a function of h/a and hu/a, for d=0.7 as average value, as the influence of d upon k is relatively small.
For this arrangement of the lateral intake, an exact hydraulic determination of the evacuated amounts of water for power generation is not possible, as the inflow into the side canal (power canal) with the aid of a repelling groin very much depends upon the flow conditions and thus also upon the water level in the river.
The rating curves of the river and the canal (relation between
water level and corresponding amount of discharge in a river/canal) allow only
the approximate amounts of water for power generation to be estimated (cf. Fig.
39).
The amounts of water for power generation are obtained from the water
level of the river and of the canal which is identical in the inlet area, thus
allowing a value to be estimated for the corresponding
discharge.
In the case of a vertical approach to a Tyrolean intake (cf. Fig. 40), amounts of water partially obstructed by the trash rack - fall into a collection canal which is intended to evacuate the water laterally. With this, a water level similar to that shown in Fig. 40 is formed above the trash rack.
Fig. 39: Lateral intake with
repelling groin
The following weir formula is used for the design of a Tyrolean intake:
(in m³/s)
where (cf. also Fig. 40) Q = discharge to be diverted in m³/s, h = k · hlimit. = 2/3 k hE = "initial water height'' in m, c = 0.6 b cos3/2 b
with a = inside width between trash rack bars in m, d = centre
distance of the trash rack bars in m, b = angle of inclination of the trash rack
with respect to the horizontal in °, m =
discharge coefficient for the trash rack, b = width of the Tyrolean intake in m,
L = length of the trash rack in m.
The various coefficients can be taken from
Fig. 40.
Fig. 40: Design of a bottom intake
(Tyrolean weir)
b |
c |
b |
c |
0° |
1.000 |
14° |
0.879 |
2° |
0.980 |
16° |
0.865 |
4° |
0.961 |
18° |
0.851 |
6° |
0.944 |
20° |
0.837 |
8° |
0.927 |
22° |
0.825 |
10° |
0.910 |
24° |
0.812 |
12° |
0.894 |
26° |
0.800 |
values k
The oblique arrangement of the trash rack prevents
it from being clogged by bed load or floating matter and the intake from being
obstructed. The Tyrolean intake is particularly suitable as an intake structure
in rivers transporting bed load. In order to guarantee the diversion of the
minimum amount of water when stones become wedged in the trash rack, or branches
and leaves remain on the trash rack at low water levels, the trash rack should
be
selected L = 1.2 · Lcalculated
The collection canal should be designed according to the
following principles:
- The canal width should correspond approximately to the length L of the trash rack.
Exactly: B = L cos b, b = angle of inclination of the trash rack bars with respect to the horizontal.
- The canal depth for the evacuation of the water should approximately correspond to the canal width: t ~ B.
- The canal depth is to be so determined that a freeboard of approx. 0.25 · t (t = water depth necessary for the evacuation of the water!) remains up to the upper edge of the trash rack. If the water cannot be evacuated in accordance with the above recommendations, either the gradient or the water depth t of the collection canal must be increased.
- The amount of water for power generation is limited by the capacity of the canal cross-section.